Hvor mange molekyler af atomer hvert element er der i en mol ammoniumcarbonat?

1. Identificer elementerne:

* nitrogen (n)

* brint (H)

* carbon (c)

* ilt (O)

2. Bestem antallet af atomer pr. Molekyle:

* nitrogen (n): 2 atomer pr. Molekyle (på grund af underskriften 2 uden for parenteserne)

* brint (H): 8 atomer pr. Molekyle (2 ammoniumioner x 4 brintatomer pr. Ion)

* carbon (c): 1 atom pr. Molekyle

* ilt (O): 3 atomer pr. Molekyle

3. Avogadros nummer:

* En mol af ethvert stof indeholder 6,022 x 10²³ partikler (atomer, molekyler osv.).

Derfor i en mol ammoniumcarbonat:

* nitrogen (n): 2 atomer/molekyle x 6,022 x 10²³ molekyler/mol =1,2044 x 10²⁴ atomer

* brint (H): 8 atomer/molekyle x 6,022 x 10²³ molekyler/mol =4,8176 x 10²⁴ atomer

* carbon (c): 1 atom/molekyle x 6,022 x 10²³ molekyler/mol =6,022 x 10²³ atomer

* ilt (O): 3 atomer/molekyle x 6,022 x 10²³ molekyler/mol =1,8066 x 10²⁴ atomer