1. Konverter masser til mol
* Nikkel (Ni): 0,587 g Ni / 58,69 g/mol Ni =0,0100 mol Ni
* Klor (Cl): 1.065 g Cl₂ / 70.90 g/mol Cl₂ =0.0150 mol Cl₂
* Note:We use the molar mass of Cl₂ (70.90 g/mol) because chlorine gas exists as a diatomic molecule (Cl₂).
2. Bestem molforholdet
* Divide the number of moles of each element by the smallest number of moles:
* Ni:0,0100 mol / 0,0100 mol =1
* Cl:0,0150 mol / 0,0100 mol =1,5
3. Find det enkleste hele talforhold
* Since we have a ratio of 1:1.5, we need to multiply both sides by 2 to get whole numbers:
* Ni:1 x 2 =2
* Cl:1,5 x 2 =3
4. Skriv den empiriske formel
* The empirical formula of the nickel chloride product is NiCl₃ .
Vigtig bemærkning: Nikkelchlorid findes normalt som NiCl2. The reaction described in this problem might produce a different, less common form of nickel chloride with a 1:3 ratio of nickel to chlorine.
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