Hvor mange molekyler er der i 720 gram C6H12O6?

1. Find den molære masse af glukose (C6H12O6):

* Carbon (C):6 atomer * 12,01 g/mol =72,06 g/mol

* Hydrogen (H):12 atomer * 1,01 g/mol =12,12 g/mol

* Oxygen (O):6 atomer * 16,00 g/mol =96,00 g/mol

* Samlet molmasse:72,06 + 12,12 + 96,00 = 180,18 g/mol

2. Konverter gram glukose til mol:

* Mol =(masse i gram) / (molmasse)

* Mol =720 g / 180,18 g / mol =4 mol

3. Brug Avogadros nummer for at finde antallet af molekyler:

* Avogadros nummer:6,022 x 10^23 molekyler/mol

* Antal molekyler =(mol) * (Avogadro's nummer)

* Antal molekyler =4 mol * 6,022 x 10^23 molekyler/mol = 2,409 x 10^24 molekyler

Derfor er der ca. 2,409 x 10^24 molekyler i 720 gram glukose.